General Organic Chemistry MCQ Questions & Answers in Organic Chemistry | Chemistry
Learn General Organic Chemistry MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
181.
The correct statement regarding a carbonyl compound with a hydrogen atom on its
alpha-carbon, is
A
a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as aldehyde-ketone equilibration
B
a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as carbonylation
C
a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism
D
a carbonyl compound with a hydrogen atom on its alpha-carbon never equilibrates with its corresponding enol
Answer :
a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism
In keto-enol tautomerism, a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol.
182.
$$C{H_3} - CHCl - C{H_2} - C{H_3}$$ has a chiral centre. Which one of the following represents its $$R$$ -configuration?
183.
Which of the following has the most acidic hydrogen ?
A
3 - Hexanone
B
2, 4 - Hexanedione
C
2, 5 - Hexanedione
D
2, 3 - Hexanedione
Answer :
2, 4 - Hexanedione
In \[C{{H}_{3}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,C{{H}_{2}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,C{{H}_{2}}-C{{H}_{3}},\] \[-C{{H}_{2}}-\] group is flanked on both sides by electron- withdrawing groups and hence its hydrogens are most acidic. Once a carbanion is formed, it is stabilised due to resonance.
184.
Isomers of a substance must have the same
A
structural formula
B
physical properties
C
chemical properties
D
molecular formula
Answer :
molecular formula
Two or more compounds having the same molecular formula but different physical, chemical properties and structural formula are called isomers.
185.
In allene $$\left( {{C_3}{H_4}} \right),$$ the type$$(s)$$ of hybridization of
the carbon atoms is (are) :
A
$$sp\,{\text{and}}\,s{p^3}$$
B
$$s{p^2}\,{\text{and}}\,sp$$
C
$${\text{only}}\,s{p^2}$$
D
$$s{p^2}\,{\text{and}}\,s{p^3}$$
Answer :
$$s{p^2}\,{\text{and}}\,sp$$
186.
What are the hybridization and shapes of the following molecules?
$$\eqalign{
& \left( {\text{i}} \right)C{H_3}F \cr
& \left( {{\text{ii}}} \right)HC \equiv N \cr} $$
A
$$\left( {\text{i}} \right)s{p^2},$$ trigonal planar; $$\left( {{\text{ii}}} \right)s{p^3},$$ tetrahedral
B
$$\left( {\text{i}} \right)s{p^3},$$ tetrahedral ; $$\left( {{\text{ii}}} \right)sp,$$ linear
C
$$\left( {\text{i}} \right)sp,$$ linear ; $$\left( {{\text{ii}}} \right)s{p^2},$$ trigonal planar
$${C_2}{H_2}$$ have acidic nature but it is less acidic than water. Phenol is more acidic than water due to resonance stabilisation of phenoxide ion. $${H_2}C{O_3}$$ is most acidic due to resonating stabilisation of carbonate ion $$\left( {CO_3^{2 - }} \right).$$
Thus, the correct order is
$${C_2}{H_2} < {H_2}O < phenol < {H_2}C{O_3}$$
190.
Separation of two substances by crystallisation depends upon their differences in
A
densities
B
solubility
C
melting points
D
boiling points
Answer :
solubility
Crystallisation is based on the difference in the solubilities of the compound and the impurities in a suitable solvent.