151. An unsaturated hydrocarbon was treated with ozone and resulting ozonide on hydrolysis gives 2-pentanone and acetaldehyde. What is the structure of alkene?
A
B
C
D
Answer :
152. Addition of $$HI$$ to double bond of propene yields isopropyl iodide and not $$n$$ - propyl iodide as the major product, because addition proceeds through
A
a more stable carbonium ion
B
a more stable carbanion
C
a more stable free radical
D
homolysis
Answer :
a more stable carbonium ion
153. Which one of the following reactions is expected to readily give a hydrocarbon product in good yields ?
A
\[RCOOK\xrightarrow[\text{oxidation}]{\text{Electrolytic}}\]
B
\[RCO{{O}^{-}}A{{g}^{+}}\xrightarrow{B{{r}_{2}}}\]
C
\[C{{H}_{3}}C{{H}_{3}}\xrightarrow[h\upsilon ]{C{{l}_{2}}}\]
D
\[{{\left( C{{H}_{3}} \right)}_{3}}CCl\xrightarrow{{{C}_{2}}{{H}_{5}}OH}\]
Answer :
\[RCOOK\xrightarrow[\text{oxidation}]{\text{Electrolytic}}\]
154.
Arrange the following alkyl halides in decreasing order of the rate of $$\beta $$ - elimination reaction with alcoholic $$KOH.$$
\[\begin{align}
& \left( \text{i} \right)C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
H \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{2}}Br \\
& \left( \text{ii} \right)C{{H}_{3}}-C{{H}_{2}}-Br \\
& \left( \text{iii} \right)C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br \\
\end{align}\]
A
(i) > (ii) > (iii)
B
(iii) > (ii) > (i)
C
(ii) > (iii) > (i)
D
(i) > (iii) > (ii)
Answer :
(i) > (iii) > (ii)
155. Propanal-1 and pentan-3-one are the ozonolysis products of an alkene. What is the structural formula of alkene?
A
\[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}C{{H}_{3}}\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{-C=CH-}}\,C{{H}_{2}}C{{H}_{3}}\]
B
\[C{{H}_{3}}C{{H}_{2}}-CH=\overset{\begin{smallmatrix}
\,\,\,\,\,\,\,\,C{{H}_{2}}C{{H}_{3}} \\
|\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{CH-CH-C{{H}_{3}}}}\,\]
C
\[\underset{\begin{smallmatrix}
\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{2}}C{{H}_{3}}
\end{smallmatrix}}{\mathop{C{{H}_{3}}-C=}}\,\overset{\begin{smallmatrix}
C{{H}_{2}}C{{H}_{3}}\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{C-C{{H}_{3}}}}\,\]
D
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}-CH=\] \[CH-C{{H}_{2}}C{{H}_{3}}\]
Answer :
\[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}C{{H}_{3}}\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{-C=CH-}}\,C{{H}_{2}}C{{H}_{3}}\]
156. The major product obtained in the photo catalysed bromination of 2-methylbutane is :
A
1-bromo-2-methylbutane
B
1-bromo-3-methylbutane
C
2-bromo-3-methylbutane
D
2-bromo-2-methylbutane
Answer :
2-bromo-2-methylbutane
157.
Complete the following reactions :
\[\left( \text{i} \right){{C}_{2}}{{H}_{5}}I+{{H}_{2}}\xrightarrow[{{C}_{2}}{{H}_{5}}OH]{Zn\,-\,Cu}X\]
\[\left( \text{ii} \right)C{{H}_{3}}COONa+{{H}_{2}}O\] \[\xrightarrow{\text{Electrolysis }}Y\]
\[\left( \text{iii} \right)C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] \[\xrightarrow[773\,K]{\frac{C{{r}_{2}}{{O}_{3}}}{A{{l}_{2}}{{O}_{3}}}}Z\]
A
$$X = {C_2}{H_6},Y = {C_2}{H_6},Z = {C_6}{H_6}$$
B
$$X = C{H_4},Y = C{H_3}COOH,$$ $$Z = C{H_3}C{H_3}$$
C
$$X = {C_2}{H_6},Y = C{H_4},Z = {C_4}{H_{10}}$$
D
$$X = {C_2}{H_6},Y = C{H_4},Z = {C_5}{H_{10}}$$
Answer :
$$X = {C_2}{H_6},Y = {C_2}{H_6},Z = {C_6}{H_6}$$
158. Which of the following compounds will show $$cis{\text{ - }}trans{\text{ }}$$ isomerism?
A
$${\left( {C{H_3}} \right)_2}C = CH{C_2}{H_5}$$
B
$${H_2}C = CC{l_2}$$
C
$$C{H_3}HC = CClC{H_3}$$
D
$$HClC = C{H_2}$$
Answer :
$$C{H_3}HC = CClC{H_3}$$
159.
Identify the product for the following reaction:
$$CH \equiv CH + HOCl \to $$
A
$$C{l_2}CHCHO$$
B
$$CH\left( {OH} \right) = CHCl$$
C
$$ClC{H_2}C{H_2}OH$$
D
$$C{H_3}COCl$$
Answer :
$$C{l_2}CHCHO$$
160.
\[\xrightarrow{B{{r}_{2}}/hv}\text{Major}\left( X \right)\xrightarrow[KOH/\Delta ]{\text{Alcoholic}}\] \[\text{Major}\left( Y \right)\xrightarrow[\text{Peroxide}]{H-Br}\text{Major}\left( Z \right)z\] is :
A
B
C
D
Answer :
