Hydrocarbons (Alkane, Alkene and Alkyne) MCQ Questions & Answers in Organic Chemistry | Chemistry
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211.
Ozonolysis of an organic compound gives formaldehyde as
one of the products. This confirms the presence of :
A
two ethylenic double bonds
B
a vinyl group
C
an isopropyl group
D
an acetylenic triple bond
Answer :
a vinyl group
Compound must contain a vinyl group
in order to give formaldehyde as one of the product
212.
The distance between two adjacent carbon atoms is largest in
A
benzene
B
ethene
C
butane
D
ethyne
Answer :
butane
The $$C-C$$ bond length is maximum for single bond, butane have largest $$C-C$$ bond length because it contains carbon-carbon single bond.
213.
Complete the reaction with suitable reagents and compounds.
A
$$\left( A \right){\text{ - }}C{H_4},\left( B \right){\text{ - }}{C_6}{H_5}CHO,$$ $$\left( C \right){\text{ - }}{C_6}{H_5}COONa,\left( D \right){\text{ - }}C{H_4}$$
B
$$\left( A \right){\text{ - }}C{H_3}Cl,\left( B \right){\text{ - }}{C_6}{H_5}COOH,$$ $$\left( C \right){\text{ - }}{C_6}{H_5}COONa,\left( D \right){\text{ - alc}}{\text{.}}\,KOH$$
C
$$\left( A \right){\text{ - }}C{H_3}Cl,\left( B \right){\text{ - }}{C_6}{H_5}COOH,$$ $$\left( C \right){\text{ - }}{C_6}{H_5}COONa,\left( D \right){\text{ - }}NaOH + CaO$$
D
$$\left( A \right){\text{ - }}C{H_3}COCl,\left( B \right){\text{ - }}{C_6}{H_5}CHO,$$ $$\left( C \right){\text{ - }}{C_6}{H_5}COONa,\left( D \right){\text{ - }}AlC{l_3}$$
Answer :
$$\left( A \right){\text{ - }}C{H_3}Cl,\left( B \right){\text{ - }}{C_6}{H_5}COOH,$$ $$\left( C \right){\text{ - }}{C_6}{H_5}COONa,\left( D \right){\text{ - }}NaOH + CaO$$
214.
In the reaction, \[C{{l}_{2}}+C{{H}_{4}}\xrightarrow{H\upsilon }C{{H}_{3}}Cl+HCl\] presence of a small amount of oxygen
A
increases the rate of reaction for a brief period of time
B
decreases the rate of reaction for a brief period of time
C
does not affect the rate of reaction
D
completely stops the reaction
Answer :
decreases the rate of reaction for a brief period of time
Halogenation of alkanes follows free radical mechanism and presence of a small amount of oxygen can slow down the reaction for a period of time depending upon the amount of oxygen. Oxygen reacts with methyl free radical to form less reactive free radical and acts as an inhibitor.
215.
Which of the following has the lowest boiling point?
A
2-Methylbutane
B
2-Methylpropane
C
2, 2-Dimethylpropane
D
$$n$$ - Pentane
Answer :
2-Methylpropane
For the compounds with same molecular mass, boiling point decreases with increase in branching. Boiling point also increases with increase in molecular mass.
216.
Arrange the following in decreasing order of reactivity towards $$EAS$$ ( electrophilic aromatic substitution )
A
$$a > b > c$$
B
$$c > b > a$$
C
$$a > c > b$$
D
$$c > a > b$$
Answer :
$$a > b > c$$
$$ - C{H_3} > - C{D_3} > - C{T_3}$$
Order of hyperconjugation on the basis of bond energy. Strong bond means less
hyperconjugation.
217.
When propyne is treated with aqueous $${H_2}S{O_4}$$ in presence of $$HgS{O_4}$$ the major product is
Only addition of $$HBr$$ gives anti-Markownikoff's product in presence of peroxide. Presenceof peroxide does not make any difference while reacting with $$HCl.$$
219.
Which of the following statements is incorrect regarding dehydrohalogenation of alkenes ?
A
During the reaction hydrogen atom is eliminated from the $$\beta {\text{ - }}$$ carbon atom.
B
Rate of reaction for same alkyl group; Iodine > Bromine > Chlorine
C
Rate of reaction; $${\left( {C{H_3}} \right)_3}C - > {\left( {C{H_3}} \right)_2}CH - > C{H_3}C{H_2} - $$
D
Only nature of halogen atom determine rate of the reaction.
Answer :
Only nature of halogen atom determine rate of the reaction.
Nature of halogen atom and the alkyl group both determine rate of reaction.
220.
Which of the following compounds does not dissolve in conc. $${H_2}S{O_4}$$ even on warming ?
A
ethylene
B
benzene
C
hexane
D
aniline
Answer :
hexane
$$\eqalign{
& C{H_2} = C{H_2} + {H_2}S{O_4} \to C{H_3}C{H_2}OS{O_3}H \cr
& {C_6}{H_6} + {H_2}S{O_4} \to {C_6}{H_5}S{O_3}H + {H_2}O \cr
& {C_6}{H_{14}} + {H_2}S{O_4} \to {\text{No reaction}} \cr
& {C_6}{H_5}N{H_2} + {H_2}S{O_4} \to {C_6}{H_5}\mathop N\limits^ + {H_3}HSO_4^ - \cr} $$
Only hexane does not dissolve in conc. $${H_2}S{O_4}$$ even
on warming.